Note:We have stopped providing ebooks due to copy right issue.We regret for inconvenience.
Mail Us : electricaledition@gmail.com

Today in this post we are going to learn what is Voltage regulation of synchronous machine and different methods to calculate Voltage regulation of synchronous machine.

### Definition for Voltage regulation of a synchronous machine:

Voltage Regulation of synchronous machine is defined as the difference between terminal voltage at no load and terminal voltage at full load and excitation , speed must remain same.Voltage Regulation of synchronous machine is generally calculated in percentage of full load terminal voltage.

### Objectives for calculating Voltage regulation of a synchronous machine:

1. Parallel operation of alternators is affected by the voltage regulation. By calculating voltage regulation of synchronous machine we can adjust the parallel operating machines to be in synchronism.

2. Calculating voltage regulation of a synchronous machine determines the type of automatic voltage control equipment required for resisting the voltage changes.

3.When the load is thrown off voltage rise must be known because with the rise in voltage the insulation must be able to withstand this rise.

So calculation of voltage regulation of synchronous machine has a great importance.

### General expression for calculating Voltage regulation of synchronous machine:

Now let us derive general expression for calculating voltage regulation of a synchronous machine

Let E be the terminal voltage of the synchronous machine at no load. Now if the synchronous machine is given full load the terminal voltage will no longer be E because of the losses so let the terminal voltage now be V.

So general expression for Voltage regulation of a synchronous machine is given by

Voltage regulation% = (E - V / V) × 100

### Methods for calculating voltage regulation of synchronous machine:

There are two types of methods for calculating voltage regulation of synchronous machine.

2. Indirect Method.

Indirect method of calculating voltage regulation of synchronous machine can be further classified into 3 types:

3.Zero power factor method or potier method.

### Direct load test method for calculating voltage regulation of synchronous machine:

Now let's see how to calculate voltage regulation of synchronous machine by using direct load test method:

### Circuit connections for calculating voltage regulation of synchronous machine by direct load test:

1.Firstly connections are to be made as given in the circuit diagram:

2. Armature which is star connected is connected to the three phase load with the help of TPST. TPST is a switch and it means triple pole single through.

3. A rheostat is connected in series with the field winding.

4. Field winding is excited by using D.C supply and flux is adjusted by adjusting the rheostat. Flux adjustment is nothing but adjust the current flow through field winding.

### Procedure for calculating voltage regulation of synchronous machine by direct load test:

1. Adjust the prime mover such that the alternator rotates at synchronous speed Ns.

we know Eph α 𝞍 from emf equation

2. Now DC supply is given to the field winding and the current flow through field is adjusted so that the flux is adjusted such that the rated voltage is obtained at its terminals which can be seen on the voltmeter connected across the lines.

3. Now load is connected to alternator with the help of TPST switch.

4.The load is then increased such that the ammeter reads rated current. This is full load condition of alternator. Now as load is connected due to armature reaction there is loss in voltage so let the induced voltage be V.

5.Now again adjust the rheostat of the field winding to get rated voltage at alternator terminals.

6.Now remove the load by opening TPST switch and the excitation , speed should not be changed it should be same as before removing the load.

7. As there is no load there is no armature reaction the induced emf is equal to terminal voltage which is E.

Now we can calculate voltage regulation of synchronous machine by

Voltage regulation% =( E - V / V) × 100 at a specific power factor.

#### Limitations for calculating voltage regulation of synchronous machine by using direct load method:

This method is applicable only for small capacity machines for larger capacity machines it is not economical because that much load cannot be given directly.

In this way we have calculated the voltage regulation of synchronous machine by direct load test method.

For larger capacity machines voltage regulation can be calculated by Indirect method.

In the next post we can see how to calculate voltage regulation of synchronous machine by Indirect method.

You can download PDF form of voltage regulation of synchronous machines here

## Voltage Regulation Of Transformer

Hello everyone,
In this post we are going to discuss about Voltage regulation of a transformer.

Read here : Differences Between Core And Shell Type Transformers

What is meant my Voltage regulation of transformer?
Voltage regulation of a transformer may be defined as the difference between no load voltage of the secondary terminal of a transformer and full load voltage of the secondary terminal of that transformer at a certain power factor. Voltage regulation of a transformer is expressed in percentage of either no load secondary terminal voltage or full load secondary terminal voltage.

Read here : EMF Equation of Transformer & Voltage Transformation Ratio

### Objective to calculate voltage regulation of transformer:

Calculating voltage regulation of transformer gives how much efficiently the transformer is resisting the voltage changes from no load to full load. If there is no change in value of secondary voltage from no load to full load then the transformer is ideal and has voltage regulation 0%. So the lower the value of voltage regulation the higher is the performance of the transformer.

### Procedure to calculate voltage regulation of transformer:

Consider a transformer which is at no load which means the secondary of the transformer is open circuited. In this case the secondary voltage of the transformer and induced emf are same let it be E2 . Now full load is connected to the secondary of a transformer. In this case current I2 passes in the secondary which will lead to voltage drop and is given by I2Z2. Where Z2 is called secondary impedance of transformer. During this situation primary winding will draw equivalent full load current. Because of the voltage drop the secondary voltage cannot be E2 anymore so secondary induced emf will be V2.

### Equation for calculating voltage regulation of a transformer:

Voltage regulation of transformer in percentage can be represented as:

Voltage regulation % = (E2-V2/V2)×100%. This is called regulation down. Power factor is specific.

### Calculating voltage regulation of transformer for lagging power factor:

Now lets derive the expression for calculating voltage regulation of transformer for lagging power factor.

#### Phasor diagram:

here cos𝚹2 is lagging power factor

From diagram,

OC = OA + AB + BC

OA = V2

AB = AEcos𝚹=  I2R2cos𝚹2

BC=DEsin𝚹2=I2R2sin𝚹2

Angle between OC and OD is very less so OC is approximately equal to OD.

E2 = OC = OA + AB + BC.

E= OC = V2 + I2R2cos𝚹2 + I2R2sin𝚹2

Now voltage regulation of transformer at lagging power factor is,
Voltage regulation% = (E2-V2/V2) × 100%

Voltage regulation%=( I2R2cos𝚹2I2R2sin𝚹2V2 ) ×100%.

### Calculating voltage regulation of transformer for leading power factor:

Now lets derive the expression for calculating voltage regulation of transformer for leading power factor.

#### Phasor diagram:

From diagram,

OC = OA + AB - BC

OA = V2

AB = AEcos𝚹2 = I2R2cos𝚹2

BC = DEsin𝚹2 = I2R2sin𝚹2

Angle between OC and OD is very less so OC is approximately equal to OD.

E2  = OC = OA +AB - BC.

E= OC = V2 + I2R2cos𝚹2 - I2R2sin𝚹2

Now voltage regulation of transformer at leading power factor is,
Voltage regulation% = (E2-V2/V2) × 100%

Voltage regulation%=(I2 R2cos𝚹2 - I2R2sin𝚹2 /V2 ) ×100%.

Thus we have learnt what is voltage regulation of transformer and derived expressions for voltage regulation of transformer for lagging and leading power factors.

## All Day Efficiency of Transformer/ Distribution Transformer All Day Efficiency

#### All Day Efficiency of Transformer/ Distribution Transformer All Day Efficiency

In our previous articles we have discussed transformer working,construction etc.Today we discuss one of the important parameter of distribution transformer I.e, "all day efficiency of a distribution transformer".We know for a transformer, the efficiency is defined as the ratio of output power to input power.

Transformer Efficiency= Output Power /Input Power

The above equation is efficiency of any transformer. But for some special types of transformers such as distribution transformers power efficiency is not the true measure of the performance.For that purpose distribution transformer we calculate all day efficiency.Distribution transformer serve residential and commercial loads.

The load on distribution transformers vary considerably during the period of the day. For most period of the day these transformers are working at 30 to 40 % of full load only or even less than that. But the primary of such transformers is energised at its rated voltage for 24 hours, to provide continuous supply to the consumer.

The core loss which depends on voltage, takes place continuously for all the loads. But copper loss depends on the load condition. For no load, copper loss is negligibly small while on full load it is at its rated value. Hence power efficiency can not give the measure of true efficiency of distribution transformers. in such transformers, the energy output is calculated in kilo watt hour (kWh). Then ratio of total energy output to total energy input (output + losses) is calculated. Such ratio is called energy efficiency or All Day Efficiency of a transformer.

Based on this efficiency, the performance of various distribution transformers is compared. All day efficiency is defined as,

While calculating energies, all energies can be expressed in watt hour (Wh) instead of kilo watt hour (kWh). Such distribution transformers are designed to have very low core losses. This is achieved by limiting the core flux density to lower value by using a relative higher core cross-section i.e. larger iron to copper weight ratio.

The maximum efficiency in distribution transformers occurs at about 60-70 % of the full load. So by proper designing, high energy efficiencies can be achieved for distribution transformers. Numerical problems on all day efficiency of a transformer will be posted soon.

Related:

maximum efficiency of distribution
transformer all day efficiency of transformer pdf
efficiency of transformer formula
all day efficiency of transformer ppt
all day efficiency of transformer examples
distribution transformer efficiency in 24hrs

## No Load Test on Induction Motor / Procedure & Application

No Load Test on Induction Motor

There are three types of tests to be performed for checking the performance of an induction motor

1.No load test or open circuit test.
2.Blocked rotor test or short circuit test or locked rotor test.
3.Stator winding resistance test.
Now let's see each test in detail:

#### Main objective of conducting the no load test is:

1. To find the constant losses of the induction machine.
2. To divide constant losses into iron losses and mechanical losses.
3. To find shunt branch elements of the equivalent circuit.
4. To find no load power factor of the induction machine.

### Condition to conduct no load test:

1.To conduct the no load test we need to apply rated voltage and rated frequency to stator under no load condition and also the air gap flux is to be maintained constant.
2. If the power supply given to the induction machine is constant then one watt meter is enough in the circuit if not two watt meter's are required.

### Circuit diagram to conduct no load test:

#### Procedure to conduct no load test:

1. Connections are to be done as per the circuit diagram given above.
2. load connected to the motor is to be removed.
3. Now we need to supply rated voltage at rated frequency to the stator and also maintain constant air gap flux.
4. Input power can be measured with the help of two watt meters connected in the circuit.
5. Ammeter and voltmeter connected in the circuit gives no load voltage and current.
6. As said there is no load given to the motor the total input power given to the motor is equal to the sum of constant iron loss, mechanical losses like friction and windage losses and copper loss but it is in small amount.
7. Copper losses at rotor side can be neglected in no load test because the slip is small at no load.

Experiment values table:

 P1 P2 ILINE VLINE

Equivalent circuit:

at no load as slip is very less we can take slip approximately equal to zero.
R2'( 1/s -1) ≈ ∞  since no load I2r' = 0
so the equivalent circuit now gets modified as follows:

And the current flowing through xm is Iu  and R0 is I2.

Calculations:

V = Line to line voltage.
I = Average value of line currents flowing throw ammeters.
WNL  = P1  + Pwhich is input power or three phase power.
All the readings we get from the circuit are line values.

With star connected stator winding:

VNLperphase = V/√3 here v is the voltmeter reading in the circuit.
I0 perphase =  I here I is the ammeter reading in the circuit.
cosᴓ0 =  WNL / 3×VNLperphase×I0perphase
I1perphase = I0perphase × cosᴓ0.
Iuperphase = I0perphase × sinᴓ0.
R0 = VNLperphase / I2perphase.
Xm = VNLperphase / Iu perphase.

With delta connected stator winding:

VNL  = V = vlotlmeter reading of the circuit.
I0 perphase = I/√3 I is the ammeter reading.
cosᴓ0 =  WNL / 3×VNLperphase×I0perphase.
I1perphase = I0perphase × cosᴓ0.
Iuperphase = I0perphase × sinᴓ0.
R0 = VNLperphase / I2perphase.
Xm = VNLperphase / Iu perphase.

Power factor:

Based on watt meter readings we can find power factor approximately
If  P1 = P2  then power factor (lagging) = Unity.
if  P1 = 2Pthen power factor(lagging) = 0.866.
if  P2= 0 , P1 = total 3 phase power then power factor(lagging) = 0.5
if P1 = - P2 then power factor(lagging) =  Zero.

Finding out constant losses:

At no load input power supplied WNL = iron losses of stator + mechanical losses + stator copper losses.
1.Here the core losses of rotor are not considered as there is no load losses at rotor side are negligible.
2.And as there is no load mechanical power output is zero.
3.For induction machine mechanical losses are almost constant irrespective of load because of less speed variations.
Therefore iron loss of stator + mechanical losses = Constant losses.
WNL = Constant losses + stator copper loss at no load .
constant losses = WNL - stator copper losses at no load.
constant losses =  WNL - 3I02R1.
where R1 is the per phase resistance of stator winding.
R1 can be measured by using bridges.

Dividing constant losses into Iron losses and Mechanical losses:

1. We need to conduct the no lo load test using variable voltage at constant frequency.
2. By changing the applied voltage note down the readings of watt meter.
3. Now find constant losses using, constant losses = WNL - 3I02R1.

Calculating iron loss:

As frequency is constant  iron losses α V12.
V1 is the varying voltage.

Calculating mechanical loss:

1.As we said that speed is almost constant in induction motor at constant frequency the mechanical losses are constant.
2. By adding load to the induction motor and decreasing the voltage at constant frequency the speed of induction motor falls to maintain load torque constant so mechanical losses will decrease. If applied voltage becomes zero iron losses will become zero.
Now draw the graph and from graph we can calculate the values of mechanical loss and iron loss.
Test has to be conducted from Vrated to Vmin.

In this way we can find out Iron losses and mechanical losses.
Now  all the objectives of No load test are fulfilled and hence the performance of machine can be known.

As our part of free ebooks for electrical engineers today we are uploading  Power System book by C L Wadhwa it is a very important book of power systems . Power systems is a very important topic of electrical engineering to understand that well you need to read good book of that.So here we are sharing Electrical power systems by cl wadhwa.